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Q.

A man $M_{1}$ of mass 80 kg runs up a staircase in 15s. Another man $M_{2}$ also of mass 80 kg runs up the staircase in 20s. The ratio of the power developed by them will be

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a

\frac{3}{4}

b

\frac{4}{3}

c

1

d

\frac{16}{9}

answer is A.

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Detailed Solution

M_{1} = 80 {kg,t}_{1} = 15 s

$\Rightarrow M_{2} = 80 {kg,t}_{2} = 20 s$

Power of $m_{1} \Rightarrow P_{1} = \frac{w_{1}}{t_{1}}$

Power of $m^{2} \Rightarrow P_{2} = \frac{w_{2}}{t_{2}} {(here w}_{1} = w_{2})$

$\frac{P_{1}}{P_{2}} = \frac{t_{2}}{t_{1}} = \frac{4}{3}$

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A man M1 of mass 80 kg runs up a staircase in 15s. Another man M2 also of mass 80 kg runs up the staircase in 20s. The ratio of the power developed by them will be