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Q.

A man (mass = 50 kg) and his son (mass = 20 kg) ) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms-1 with respect to the man. The speed of the man with respect to the surface is 

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a

0.20 ms-1

b

0.47 ms-1

c

0.14 ms-1

d

0.28 ms-1

answer is A.

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Detailed Solution

Let v1 and v2 be their velocities after pushing.

Given, v1+v2=0.7

Applying law of conservation of momentum,

 m1v1 = m2v2

50 × v1 = 20 × v2 5v1  = 2 v2 So, v1 =0.2 ms-1

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