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A man moves from A to B. A large part of the distance is uphill and he gets a mileage of only 10 miles per gallon of gasoline. On the return trip, he makes 15 miles per gallon, then the average of his mileage (assuming that the distance from A to B is 60 miles) is

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Detailed Solution

$d_{1} = d_{2} = 60$

Average of his mileage $= \frac{2 d}{\frac{d}{10} + \frac{d}{15}} = 12$

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