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A man moves on straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of $0.5 {m/s}^{2}$ , work done by the man on the block during the motion is

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4000 J

400 J

40 J

0.4 J

answer is C.

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Detailed Solution

$W = F . S$ = (massxacceleration).S

$= 2 \times 0 .5 \times 40$

$= 2 \times \frac{1}{2} \times 40$

$= 40 J$

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