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A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficency is 56%. To what height he can jump by using this energy?

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20 m

28 m

0.2 m

answer is A.

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Detailed Solution

$\begin{array}{l} m = 60 kg, Q = J \times 1000 J = 4 .2 \times 1000 = 4200 J \\ = 4200 \times \frac{56}{100} = 42 \times 56 J \\ mgh = Q \Rightarrow h = \frac{Q}{mg} \frac{^{7} 42 \times 56^{4}}{^{10} 60 \times 98 0.1} \\ h = 4 m \end{array}$

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