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A man of mass 40 kg is at rest between the walls as shown in the figure. If  μbetween the man and the walls is 0.8, find the normal reaction exerted by the walls on the man. (g=10ms–2)

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a
100N
b
250N
c
80N
d
50N

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detailed solution

Correct option is B

The frictional force from the two sides will be balancing the weight of man.

2μN=mgN=mg2μ=4002(0.8)=250N

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