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A man of mass 50 kg stands on a frame of mass 30 kg. He pulls on a light rope which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium what force man must exert on the rope?

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40 g

80 g

30 g

50 g

answer is A.

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Detailed Solution

Force exerted by man on rope transfers to it in the form of tension.

Net upward force on the system is 2T or 2F.

Net downward force is (50+30)g = 80 g

For equilibrium of system, 2F = 80g or F = 40g

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