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A man of mass 50kg is standing at one end on a boat of length 25m and mass 200kg. If he starts running and when he reaches the other end, he has a velocity 2m/s with respect to the boat. The final velocity of the boat is $4 \times 10^{- n} m / s$ , here ___

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answer is 1.

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Detailed Solution

$V_{B} = \frac{{mV}_{mB}}{m + M} = \frac{50 \times 2}{50 + 200} = \frac{2}{5} = 0 .4$

$V_{B} = 4 \times 10^{- 1} \Rightarrow n = 1$

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