A man of mass 60 kg hangs himself from a massless spring balance. Which itself suspended from an ideal string-pulley system as shown in the figure. The string AB can bear maximum $900 N$ . Choose correct statement.

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The maximum magnitude of acceleration, man can manage is $12.5 m / s^{2}$ while Moving upward.

If man able to manage himself at rest, the spring balance reads his true weight.

The man is never ever able to read his correct weight in the spring balance.

When man moves downward with acceleration $5 m / s^{2}$ , the spring balance will read $40 k g$ .

answer is C.

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Detailed Solution

$\begin{array}{l} 2 T - M g + T = M a \Rightarrow M g - 3 T = M a \Rightarrow 3 T = M (g - a) \dots (i) \\ 2T = kx \\ T = \frac{M (g + a)}{a} \end{array}$

Reading of spring balance will be

$= \frac{k x}{g} = \frac{2 T}{g} = \{\begin{cases} \frac{2 M (g + a)}{3 g} (When moving upward) \\ \frac{2 M (g - a)}{3 g} (When moving downward) \end{cases}$