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A man of mass 60 kg is standing on a stationary boat of mass 240 kg. The man is carrying a sphere of mass 0.5 kg in his hands. If the man throws the sphere horizontally with a velocity of _{$12 m s^{- 1}$} , find the velocity with which the boat will move (in magnitude)

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_{$0.5 m s^{- 1}$}

_{$0.06 m s^{- 1}$}

_{$0.02 m s^{- 1}$}

_{$0.04 m s^{- 1}$}

answer is A.

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Detailed Solution

_{$(M + m) v_{1} = m^{|} v_{2}$}

_{$300 \times v_{1} = 0.5 \times 12$}

_{$v_{1} = 0.02 m s^{- 1}$}

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