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Q.

A man of mass 60 kg sitting on ice pushes a block of mass of 12 kg on ice horizontally with a speed of 5 ms-1.The coefficient of friction between the man and ice and between block and ice is 0.2. If g =10 ms-2,the distance between man and the block, when they come to rest is

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a

6 m

b

6.5 m

c

3 m

d

7 m

answer is B.

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Detailed Solution

S1=v22μg,according to law of conservation of momentum, 

S2=v122μg; 

find v1; 60v'+12×5=0

v'=-1m/s

S=S1+S2

=v22μg+v122μg=12μg52+12=6.5 m

 

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