Q.

A man of mass ‘m’ is standing on an elevator that is moving down with acceleration "g5".
The force exerted by the elevator on the man is

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a

2mg5

b

4mg5

c

8mg5

d

6mg5

answer is A.

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Detailed Solution

FBD of the man
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mgN=mg5N=mg115=4mg5

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A man of mass ‘m’ is standing on an elevator that is moving down with acceleration "g5".The force exerted by the elevator on the man is