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A man of mass m stands on a platform of equal mass m and pulls himself by two ropes passing over pulleys as shown in figure. If he pulls each rope with a force equal to half his weight, his upward acceleration would be

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$\frac{g}{2}$

zero

$\frac{g}{4}$

answer is D.

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Detailed Solution

$\begin{array}{l} F = 4 (\frac{mg}{2}) \to upwards \\ W = 2 mg \to downwards \\ F = W, ∴ a = 0 \end{array}$

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