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A man running uniformly at $8 m / s$ is $16 m$ behind a bus when it starts accelerating at $2 m s^{- 2} .$ Time taken by him to board the bus is

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answer is C.

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Detailed Solution

16 $= 8 t - \frac{1}{2} \times 2 t^{2}$ (equation relative to bus)
t = 4s

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