A man runs across the roof of a tall building and jumps horizontally on (lower) roof of an adjacent building. If his speed is 9 m/s and the horizontal distance between the building is 10m and the height difference between the roofs is 9 m, will he be able to land on the next building ? (Take g = 10 m/s²)

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Detailed Solution

Horizontal speed: u = 9m/s
given range: R = 10 m
vertical displacement: h = 9m
$range: R^{'} = u \sqrt{\frac{2 h}{g}} = 9 \sqrt{\frac{2 \times 9}{10}}$
$= 9 \sqrt{1 .8} = 9 \times 1 .34 = 12 .06 m$
$∵ R^{'} > R$ , therefore, he will be able to land on next building.

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