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Q.

A man saved Rs.16,500 in ten years. In each year after the first, he saved Rs.100 more than he did in the preceding year. How much did he save in the first place?

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a

Rs.1200

b

Rs.1300

c

Rs.1400

d

Rs.1400

answer is A.

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Detailed Solution

Let the amount saved by the man in his first year be Rs.x. By reading the given statement, it can be stated that he saved Rs.(x+100) in the second year. And Rs.(x+200) in the third year. Following this rule, he would have saved Rs.(x+900) in the tenth year.
Therefore, we have the following A.P –
x,x+100,x+200,x+300,x+400,.....,x+900
We will use the formula of A.P –Sn=16500,n=10,d=100
Sn=

\frac{n}{2}

[2a+(n−1)d]
16500=

\frac{10}{2}

[2x+(10−1)100]
16500=5[2x+900]
16500=10x+4500
10x=12000
x=1200
Hence he saves Rs. 1200 in first year.
Hence, The correct answer is option (1).

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A man saved Rs.16,500 in ten years. In each year after the first, he saved Rs.100 more than he did in the preceding year. How much did he save in the first place?