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A man standing at some distance from a cliff hears the echo of sound after 2 sec. He walks 495 m away from the cliff. He produces a sound there and receives the echo after 5 sec. What is the speed of sound (in m/s)?

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answer is 330.

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Detailed Solution

$t_{A C} = \frac{2 d}{V_{3}} = 2 \sec$

$t_{B C} = \frac{2 (495 + d)}{V_{S}} = 5 \sec \frac{990}{V_{s}} + \frac{2 d}{V_{s}} = 5 \frac{990}{V_{s}} + 2 = 5 \frac{990}{V_{s}} = 3 V_{s} = \frac{990}{3} V_{s} = 330 m / s$

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