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Q.

A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340ms^-1, the distance between the cliffs is

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a

1700 m

b

1620 m

c

340 m

d

680 m

answer is A.

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Detailed Solution

Total time taken for both the echoes $t = t_{1} + t_{2} = 2 \sec$

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but $t = \frac{2 d_{1}}{v} + \frac{2 d_{2}}{v} \Rightarrow t = \frac{2}{v} (d_{1} + d_{2})$

$\Rightarrow (d_{1} + d_{2}) = \frac{v \times t}{2} = \frac{340 \times 2}{2} = 340 m$

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