A man travels $600 km$ partly by train and partly by car. It takes $8 h$ and $40 min$ ,if he travels $320 km$ by train and the rest by car. It would take 30 min more, if he travels $200 km$ by train and the rest by car. Find the speed of the train and the car separately.

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Speed of the train is 30 km/h and the speed of the car is 10 km/h.

Speed of the train is 90 km/h and the speed of the car is 40 km/h.

Speed of the train is 80 km/h and the speed of the car is 60 km/h.

Speed of the train is 60 km/h and the speed of the car is 70 km/h.

answer is C.

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Detailed Solution

Given that a man travels 320 km by train and 280 km by car, in 8h and 40 min,
He travels 200 km by train and 400 km by car, in 9h and 10 min,
According to given condition,
Let the speed of train be x km/h and that of car be y km/h then,

320 x + 280 y = 263 … (i) 200 x + 400 y = 556 … (i i)

On solving above equations, we get, x = 80, y = 60

Therefore, the speed of the train is 80 km/h and the speed of the car is 60 km/h.
Hence, option (3) is correct.

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