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A man turns on rotating table with an angular speed ω. He is holding two equal masses at arms length. Without moving his arms, he just drops the two masses. How will his angular speed change?

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less than ω

more than ω

it will be equal to ω

it will be more than ω if the dropped mass is more than 9.8kg and it will be less than ω if the mass dropped is less than 9.8kg

answer is C.

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Detailed Solution

When the man drops the two masses, he is not exerting any torque on the rotating table.

Therefore, the angular momentum of the system (man + table + masses) remains constant.

Since the masses are equal, the angular momentum of the man and the table alone before and after the masses are dropped will be the same.

Therefore, the angular speed of the table will not change.

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