A man walks 1 km towards East then turns to South and walks 5 kms. Again he turns to East and walks 2 kms. Then he turns North and walks 9 km. How far is he from the starting point?

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2 kms

3 kms

5 kms

9 kms

answer is C.

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Detailed Solution

$AF = 3 kms, EF = 4 kms$

$∴ A E = \sqrt{3^{2} + 4^{2}} = \sqrt{9 + 16} = \sqrt{25} = 5 kms$

So, he is 5 Jans away from the starting point.

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