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Q.

A man walks on a straight road from his home to a market 2.5 km away with a Speed of 5 km h–1 Finding the market closed, he instantly turns and walks back home with a speed of 7.5 km h–1. What is the (a) magnitude of average velocity and (b) average speed of the man over the time interval 0 to 50 min.

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Detailed Solution

 (a) Average velocity = total displacemnt  total timetaken 
= Zero t= zero 
 (b) Average speed  = total distance  total time taken 
=2.5+2.5t1+t2=52.55+2.57.5=6km/h

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