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Q.

A man walks up a stationary escalator in 90s. When this man stands on a moving escalator he goes up in 60s. The time taken by the man to walk up the moving escalator is

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a

30 s

b

45 s

c

36 s

d

48 s

answer is C.

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Detailed Solution

t_{1} = 90 s, t_{2} = 60 s

$\frac{1}{t} = \frac{1}{t_{1}} + \frac{1}{t_{2}}$

$t = \frac{t_{1} t_{2}}{t_{1} + t_{2}}$

$= \frac{90 \times 60}{90 + 60}$

$= \frac{5400}{150} = 36 s$

$t = 36 s$

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