A man weighing $80 k g$ is standing in a trolley weighing $320 k g$ . The trolley is resting on frictionless horizontal rails. If the man starts walking with the speed of $1 m / s$ with respect to trolley, then after $4 s e c$ his displacement relative to the ground will be

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$5 m$

$3.2 m$

$4.8 m$

$3.0 m$

answer is C.

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Detailed Solution

Velocity of man w.r.t ground = $1 - v$ , where v is velocity of trolley w.r.t. ground
$80 (1 - v) = 320 v$
$∴$ v = 0.2 m/s
$∴$ Displacement of man w.r.t ground $= (1 - 0.2) \times 4 = 3.2 m$

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