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Q.

A man weighs 80 kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 ms-2. What would be the reading on the scale ? (g = 10 ms-2)

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a

800N

b

1200N

c

zero

d

400N

answer is B.

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Detailed Solution

Mass of man M = 80Kg
Acceleration of lift, a=5ms2  
When lift is moving upwards the reading of weighing scale will be equal to R. The equation of motion gives

RMg=Ma  or  R=Mg+Ma=Mg+aR=8010+5=80×15=1200N

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