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Q.

A man weights 80 kg on earth surface. The height above ground where he will weigh 40kg is (radius of earth is r)

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a

0.414 times r

b

0.31 times r

c

0.51 times r

d

0.61 times r

answer is B.

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Detailed Solution

gh=g1+hR2mgh=mg1+hR2⇒40kgwt=80kgwt1+hR21+hR2=2⇒1+hR=2⇒1+hR=1.414h=0.414R=0.414 r

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