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Q.

A man with colour blindness has a daughter of normal phenotype. She marries a man who is not colour blind. If the married couple had four sons, what is the possibility that all four will be colour blind?

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a

1/4

b

1/16

c

1/8

d

1/32

answer is B.

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Detailed Solution

A man with colour blindness has a daughter of normal phenotype. She marries a man who is not colour blind. If the married couple had four sons, every child birth 1/2 chance is present for male to become colour blind because she is a carrier. So for four children ½ x ½ x ½ x ½ = 1/16. 

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