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Q.

A man with defective eyes cannot see distinctly object at the distance more than 60 cm from his eyes. The power of the lens to be used will be

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a

– 60 D

b

$\frac{1}{1 .66} D$

c

+ 60 D

d

– 1.66 D

answer is C.

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Detailed Solution

$f = - d = - 60 cm ∴ P = \frac{100}{f} = - \frac{100}{60} = - \frac{10}{6} = - 1 .66 D$

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