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A manometer shown below contains a liquid of density $' ρ'$ . The difference in the levels when the manometer rotates at a constant angular velocity $ω$ about one of its vertical limbs (Let $ℓ$ be the length of horizontal tube)

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$\frac{ω^{2} ℓ^{2}}{2 g}$

$\frac{ω^{2} ℓ^{2}}{g}$

$\frac{2 ω^{2} ℓ^{2}}{g}$

$\frac{3 ω^{2} ℓ^{2}}{g}$

answer is A.

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Detailed Solution

$h = \frac{υ^{2}}{2 g} = \frac{{(ℓ ω)}^{2}}{2 g} = \frac{ω^{2} ℓ^{2}}{2 g}$

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