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Q.

A marble moving with a speed 0.2 m/s rolls off the edge of a table 20 m high. At what distance will it strike the floor from the foot of the table? $(g = 10 m / \sec)$

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a

0.1 m

b

0.2 m

c

0.4 m

d

0.3 m

answer is D.

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Detailed Solution

$R a n g e = R = U \sqrt{\frac{2 h}{g}}; g i v e n h e r e i n i t i a l v e l o c i t y U = 0.2 m / s; h e i g h t o f t h e t a b l e = 20 m; g = 10 m / s^{2} R = 0.2 \sqrt{\frac{2 \times 20}{10}} = 0.4 m = d i s \tan c e f r o m t h e f o o t o f t h e t a b l e$

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