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A mark is made on the bottom of a beaker and a liquid of refractive index 1.4 is poured to a height 5 cm. When viewed
vertically from the top, the mark seems to be raised by (in cm)

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3.57

1.43

3.14

7.0

answer is B.

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Detailed Solution

$S = t (1 - \frac{1}{μ})$
$\begin{array}{l} = 5 (1 - \frac{1}{1.4}) \\ = 5 \times \frac{0.4}{1.4} \\ = \frac{2}{1.4} = 1.43 \end{array}$

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