detailed solution

Correct option is A

Energy wasted by the mason = $\frac{1}{2}m{u}^{2}$

Fraction of energy wasted

$\frac{{\displaystyle \frac{1}{2}}m{u}^{2}}{mgh+{\displaystyle \frac{1}{2}}m{u}^{2}}\times 100=\frac{{u}^{2}}{\left(2gh+{u}^{2}\right)}\times 100$

=$\frac{36}{200+36}\times 100=\frac{36}{236}\times 100=15\%$

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