A mass 1 kg is suspended by a thread. It is
(i) lifted up with an acceleration $4 .9 m / s^{2}$
(ii) lowered with an acceleration $4 .9 m / s^{2}$ .
The ratio of the tensions is

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3 : 1

1 : 3

1 : 2

2 : 1

answer is A.

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Detailed Solution

$T_{1} = m (g + a) = 1 \times (g + \frac{g}{2}) = \frac{3 g}{2} T_{2} = m (g - a) = 1 \times (g - \frac{g}{2}) = \frac{g}{2} ∴ \frac{T_{1}}{T_{2}} = \frac{3}{1}$

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