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Q.

A mass  m=0.4kg is attached to a vertical rod by mass of two strings of equal length  I=2m. The system rotates about the axis of the rod with ω=4rad/sec, as shown. If T1  is the tension in the upper string and T2 is the tension in the lower string then ( g=10m/s2
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a

T1=3N,T2=10N

b

T1=T2+4N

c

T1=T2

d

T1=10,4N,T2=2.4N

answer is B.

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Detailed Solution

(T1+T2)cos30=mrω2=mlcos30ω2T1+T2=mlω2.........(1)(T1T2)sin30=mgT1T2=2mg..........(2)solving  T1=10.4                 T2=2.4

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