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A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when

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the mass is at the lowest point

the wire is horizontal

the mass is at the highest point

the wire is inclined at an angle of $60^{o}$ from vertical

answer is D.

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Detailed Solution

Tension in the wire is given by

The tension in the wire is maximum when the mass is at the lowest point, so the wire is most likely to break when the mass is at the lowest point.

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