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Q.

A mass m is vertically suspended from a spring of negligible mass; the system oscillates with a frequency n. What will be the frequency of the system, if a mass 4 m is suspended from the same spring?

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a

n4

b

n2

c

2n

d

4n

answer is C.

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Detailed Solution

n=12πkm

n′=12πk4m=12×12πkm

On putting the value of n we get n′=n2

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