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A mass m rests on a horizontal surface. The coefficient of friction between the mass and the surface is $μ$ . If the mass is pulled by a force F as shown in Figure, the limiting friction between the mass and the surface will be:

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$μ [mg - (F / 2)]$

$μ [mg + (F / 2)]$

$μmg$

$μ [mg - (\sqrt{3} / 2) F]$

answer is C.

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Detailed Solution

FBD of block

$N = mg - Fsin 30^{\circ} = mg - (F / 2)$

Limiting friction: $f_{L} = μN = μ [mg - (F / 2)]$

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