Q.

A mass of 0.1 kg is rotated in a vertical circle using a string of length 20 cm. When the string makes an angle 30⁰ with the vertical, the speed of the mass is 1.5 ms^–1. The tangential acceleration of the mass at that instant is

Easy

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4.9 ms^–2

9.8 ms^–2

2.45 ms^–2

19.6 ms^–2

answer is A.

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Detailed Solution

$a = gsin θ = gsin 30^{o} = 4.9 m / s^{2}$

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