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A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 m s^-2 (ii) lowered with an acceleration of 4.9 m s^-2. The ratio of tension in the first and second cases is

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3:1

1:2

1:3

2:1

answer is A.

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Detailed Solution

Case-1

Using Newton's second law of motion,

$T_{1} - m g = m a T_{1} = m (g + a)$

Case-2

Using Newton's second law of motion,

$m g - T_{2} = m a T_{2} = m (g - a)$

From 1 and 2

$\frac{T_{1}}{T_{2}} = \frac{g + a}{g - a} = \frac{9.8 + 4.9}{9.8 - 4.9} = \frac{3}{1}$

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