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Q.

A mass of 10 kg is suspended by a rope of length 2.8 m from a ceiling. A force of 98 N is applied at the mid-point of the rope as shown in figure. The angle which the rope makes with the vertical in equilibrium is

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a

30°

b

60°

c

45°

d

80°

answer is C.

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Detailed Solution

Tsin⁡θ=98N  T cos⁡θ=98 ∴tan⁡θ=1 ⇒θ=45∘

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