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Q.

A  mass of 10 kg is suspended by a rope of length 4m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45º with the vertical. Then F equals: (Take g = 10 ms-2 and the rope to be massless)

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a

75N

b

100N

c

70N

d

90N

answer is A.

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Detailed Solution

 

Question Image

Tcos45o = mg T2=100   ......(1)

Tsin45o=F T2=F              F=100N   [from equation (1)]

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