A mass of $\text{1}0\text{kg}$ is suspended vertically by a rope of length $\text{5m}$ from the roof. A force of $\text{3}0\text{N}$ is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is $\theta =ta{n}^{-1}\left(x\times {10}^{-1}\right)$. The value of $x$ is ___ $\left(g=10m/s^2\right)$