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A mass of 2 kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in Fig. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion. The spring constant is 200 N/m. What should be the minimum amplitude of the motion so that the mass gets detached from the pan ? (Take g = 10 m/s²)

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4.0 cm

8.0 cm

10.0 cm

Any value less than 12.0 cm

answer is C.

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Detailed Solution

For given conditions,
$Mg = {Mω}^{2} a = ka a = \frac{Mg}{k} = \frac{2 \times 10}{200} = 0.1 m = 10 cm$

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