A mass of 2kg is attached to a spring of force cnstant 200NM^–1. Find its time period.

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answer is 1.

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Detailed Solution

$\begin{array}{l} T = 2 π \sqrt{\frac{m}{k}} \\ T = 2 π \sqrt{\frac{2}{200}} \\ T = 2 π \times \frac{1}{10} \\ T = \frac{π}{5} = \frac{3 .14}{5} = 0 .628 \sec \end{array}$

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