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A mass of a material exists in its solid form at its melting temperature $10^{0} C$ .
The following processes then occur to the material.
Process-I : An amount of thermal energy Q is added to the material and 3/4 of the material melts.
Process-II : An identical additional amount of thermal energy Q is added to the material and the material is now a liquid at $50^{0} C$ . If the ratio of the latent heat of fusion to the specific heat of the liquid is 16X. Find X?

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answer is 5.

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Detailed Solution

$Q = \frac{3}{4} m L = \frac{m}{4} L + m s 40$

$\frac{m L}{2} = m s 40$

$\frac{L}{S} = 80$

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