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Q.

A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is θ=tan-1x×10-1. The value of x is _________.

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answer is 0.3.

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Detailed Solution

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Tsinθ=30  Tcosθ=100   tanθ=0.3

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