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A mass of $2.0 k g$ is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion. The spring constant is $200 N / m$ . What should be the minimum amplitude of the motion so that the mass gets detached from the pan $(T a k e g = 10 m / s^{2})$

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$8.0 c m$

$10.0 c m$

Any value less than $12.0 c m$

$4.0 c m$

answer is B.

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Detailed Solution

$m g - N = m a m g - 0 = m ω^{2} A A = \frac{g}{ω^{2}} = \frac{g}{k / m} = \frac{100}{200 / 2} = 0.1 m$

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