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A mass tied to a string moves in a vertical circle with a uniform speed of $5 m / s$ as shown. At the point P, the string breaks. The mass will reach a height above P of nearly ……..

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$2.16 m$

$1 m$

$0.5 m$

$1.25 m$

answer is D.

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Detailed Solution

At P velocity is vertical.

$h = \frac{v^{2}}{2 g} = \frac{(5)^{2}}{2 \times 9.8}$

$= 1.25 m$ ……nearly

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