A massless conical flask filled with a liquid is kept on a table in a vaccum. The force exerted by the liquid on the base of the flask is W₁. The force exerted by the flask on the table is W₂.

$\mathrm{a}) {\mathrm{W}}_1={\mathrm{W}}_2$

$\mathrm{b}) {\mathrm{W}}_1>{\mathrm{W}}_2$

$\mathrm{c}) {\mathrm{W}}_1<{\mathrm{W}}_2$

$$\begin{gathered} \mathrm{d}) \mathrm{The} \mathrm{force} \mathrm{exerted} \mathrm{by} \mathrm{the} \mathrm{liquid} \mathrm{on} \mathrm{the} \mathrm{walls} \\ \mathrm{of} \mathrm{the} \mathrm{flask} \mathrm{is} ({\mathrm{W}}_1-{\mathrm{W}}_2) \end{gathered}$$

A liquid exerts forces on the walls of its container that are normal to the walls and pressure behaves uniformly in all directions. As a result, the liquid's forces acting on the conical flask's sloping walls will have a net upward component. Given that the force the liquid exerts on the flask's base is ${\mathrm{W}}_1$, we can calculate the force the liquid will exert on the flask's walls as ${\mathrm{W}}_1-{\mathrm{W}}_2$.

Hence the correct answer is b and d are correct.
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