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Q.

A massless rod BD is suspended by two identical massless string AB and CD of equal lengths. A block of mass m is suspended from point P such that BP is equal to x. If the fundamental frequency of the left wire is twice the fundamental frequency of right wire, then the value of x is

A massless rod BD is suspended by two identical massless strings AB and CD  of equal lengths. - Sarthaks eConnect | Largest Online Education Community

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a

x=3l/4

b

x=l/5

c

x=4l/5

d

x=l/4

answer is A.

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Detailed Solution

fvTfAB=2f(D)

 TA8 =4TCD 

Further

Στp=0

 TAB(x)=TCD(l-x)

or

4x=l-x

(as TAB=4TC )

or

x=l/5

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